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Cisco Exam #640-801: CCNA (Cisco Press, set 1)
Test your basic networking knowledge for Cisco's entry-level certification exam with these 10 questions and answers.

courtesy of   Cisco Press

1. A and B are correct. When a switch receives a packet it does not know the destination to, it will send it out of all the interfaces except the one it heard the packet on.

2. C is correct. VTP Pruning prevents VLANs that are not configured on switches that do not use them from being sent to them.

3. A is correct. Summarization enables groups of IP addresses to be grouped together and represented with a single entry in the routing table.

4. A is correct. The “debug isdn q921” command will show information in real-time about the LAPD protocol.

5. B and D are correct. The other possibilities are mismatched dead intervals and mismatched area numbers. The dead intervals must match for the routers to become neighbors, and the dead interval defaults to four times the Hello interval, but the dead interval does not have to be four times the Hello interval.

6. B is correct. The shorthand notation /27 = 3 subnet bits in the last octet = decimal 255.255.255.224. Shortcut: 256 - 224 = 32. Valid subnets are multiples of 32 (32, 64, 96, 128, etc).

7. B is correct.

ARP (Address Resolution Protocol) uses broadcasts to find the MAC address associated with a known IP address.
DNS (Domain Name Service) associates names with IP addresses.
ICMP (Internet Control Message Protocol) is comprised of a series of protocols used to test connectivity.
DHCP (Dynamic Host Configuration Protocol) is used to dynamically configure IP information on hosts.

8. C is correct. The bridge will first create an entry in its MAC table for the new address, then forward the frame appropriately.

9. A and B are correct. STP is a standards based protocol that creates a topology where no loops can exist. Because it blocks ports that may cause a loop, it does not use redundant links actively.

10. A is correct. The broadcast address is the address in which the host portion of the address is all 1s. This address can be easily found by subtracting one from the next subnet address.

In this case, our mask of 255.255.255.248 tells us that subnets occur at multiples of 8. We are on the 192.168.26.8 255.255.255.248 subnet, which makes the next subnet 192.168.26.16. If you subtract 1 from 16 you get 15. The broadcast address for our subnet is 192.168.26.15.

Questions and answers provided by Cisco Press. To order the full version of this exam simulation, click here.

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